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Voltage Divider Calculator

Output voltage of a two-resistor divider (Vout = Vin·R2/(R1+R2)), the current and power in each resistor, and how a load resistance pulls the output down.

Voltage Divider Calculator: with the default inputs, output voltage (vout) is 3.8367.

V
Ω
Ω
Try an example
Output voltage (Vout)
3.8367

Volts across R2 (and the load, if any).

Unloaded output voltage (V)
3.8367
Divider ratio Vout ÷ Vin
0.3197
Current through R1 (mA)
0.8163
Power in R1 (mW)
6.664
Power in R2 (mW)
3.132
Power in load (mW)
0
Total power drawn (mW)
9.796
Effective bottom resistance R2 ∥ RL (Ω)
4,700
Assumptions
  • Ideal resistors at nominal value (tolerance not modelled).
  • Ideal source with zero output impedance.
  • DC or low-frequency operation; no stray capacitance.
How much a load pulls the output down
0123100 Ω1 kΩ10 kΩ100 kΩ1 MΩ10 MΩLoad resistance
Vout with that loadUnloaded Vout
Loading effect: output vs. load resistance
Load (Ω)Vout (V)Drop vs. unloaded
∞ (no load)3.83670%
1,000,0003.82450.32%
100,0003.71793.1%
10,0002.907224.23%
1,0000.914176.18%
1000.116496.97%

The first row is the unloaded divider. A load much larger than R2 barely matters; a load comparable to R2 pulls the output well below the design value.

Math verified by automated testsUpdated 2026-09-082 sources cited

How this is worked out

The formula

Vout = Vin × R2 ÷ (R1 + R2)

With a load RL across R2, replace R2 with R2 ∥ RL = R2·RL ÷ (R2 + RL)

I = Vin ÷ (R1 + R2)       P₁ = I²R1       P₂ = Vout² ÷ R2

Open How it’s calculated above to see this worked through with your own numbers.

What you enter

Input voltage (Vin)
A number.defaults to 12
R1 (top resistor)
Between Vin and the output. 10 kΩ = 10000.0 or more · defaults to 10000
R2 (bottom resistor)
Between the output and ground.0 or more · defaults to 4700
Load resistance(under More options)
Resistance connected across R2 (an ADC input, a gate, a meter). Leave 0 for no load.0 or more · defaults to 0

What you get back

Output voltage (Vout)main answer
Volts across R2 (and the load, if any).
Unloaded output voltage (V)
Divider ratio Vout ÷ Vin
Current through R1 (mA)
Power in R1 (mW)
Power in R2 (mW)
Power in load (mW)
Total power drawn (mW)
Effective bottom resistance R2 ∥ RL (Ω)

What this assumes

  • Ideal resistors at nominal value (tolerance not modelled).
  • Ideal source with zero output impedance.
  • DC or low-frequency operation; no stray capacitance.

About this calculator

Two resistors in series split a voltage in proportion to their resistances: the output taken between them is Vin × R2 ÷ (R1 + R2). It is the simplest circuit in electronics and one of the most used — scaling a 12 V battery down to something a 3.3 V microcontroller pin can read, biasing a transistor, turning a resistive sensor (thermistor, photoresistor, potentiometer) into a voltage. Enter Vin and the two resistors; the calculator gives the output, the current, and the power each resistor must handle.

The loading effect

The textbook formula assumes nothing is connected to the output. Anything you connect — an ADC input, a transistor base, a voltmeter — has its own resistance in parallel with R2, which lowers the effective R2 and drags the output down. Open More options, enter the load, and the calculator shows the real output next to the unloaded one, plus a table of how the output sags as the load gets heavier. The rule of thumb: keep R2 at most a tenth of the load resistance and the error stays under about 10%; a hundredth keeps it near 1%.

Choosing resistor values

The ratio sets the voltage; the absolute values set the trade-off between wasted current and stiffness. 1 kΩ + 470 Ω from 12 V burns 98 mW continuously; 100 kΩ + 47 kΩ gives the same 3.84 V at 1 mW but is easily loaded and picks up noise. Microcontroller ADC inputs usually want a source impedance under 10 kΩ, so 10 kΩ + 4.7 kΩ is a common compromise.

Common mistakes

  • Swapping R1 and R2. R2 is the one the output is measured across (to ground); a bigger R2 means a bigger output.
  • Using a divider as a power supply. It cannot regulate: current drawn by the load changes the output. Use a regulator for anything that draws real current.
  • Ignoring tolerance. Two 5% resistors can put the ratio off by up to about 10%; use 1% parts when the voltage matters.
  • Forgetting power ratings when Vin is high. The steps list P = I²R for each resistor.

Frequently asked questions

What is the voltage divider formula?

Vout = Vin × R2 ÷ (R1 + R2), where R2 is the resistor between the output and ground. The output is the fraction of the input equal to R2's share of the total resistance.

Why does my divider output drop when I connect something?

The connected device's input resistance sits in parallel with R2, lowering the effective R2 and the ratio. Use smaller resistor values (so the load is at least 10× R2) or add an op-amp buffer.

How do I pick resistor values for a specific output?

Choose the ratio R2 ÷ (R1 + R2) = Vout ÷ Vin, then scale both to a size that gives acceptable current. For 5 V → 3.3 V the ratio is 0.66, so R2 = 2 × R1; 1 kΩ and 2 kΩ or 10 kΩ and 20 kΩ both work.

Can a voltage divider power a circuit?

Only very light, constant loads. Any change in load current changes the output, and the resistors waste power continuously. Use a linear or switching regulator for real supplies.

How much power does each resistor dissipate?

P = I²R with I = Vin ÷ (R1 + R2), or equivalently V²/R using the voltage across each resistor. The calculator lists both in milliwatts so you can check against the usual ¼ W rating.

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